John Egbert (
fireflyheir) wrote in
luministi2012-08-09 09:15 pm
![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png)
![[community profile]](https://www.dreamwidth.org/img/silk/identity/community.png)
[video]
[previously unknown secondary uses for windsock hoodies: impromptu scarves, which John has wrapped around most of his face, because what even is this. Admittedly it doesn't help the arm situation much, but that's what he's trying to find a jumper for.]
Okay, it wasn't this cold last time! It can't have been that long. [with a glance at the ceiling] Seriously, what is this place's deal?
Okay, it wasn't this cold last time! It can't have been that long. [with a glance at the ceiling] Seriously, what is this place's deal?
[video] :D
Oh. Yeah, that does sound pretty nice. [his gaze drops away for a moment, and then comes back] But… I guess you wouldn't want to replace the people you already have.
[video]
No, but I didn't...mind, having sisters and uncles and things like that. Even though they didn't like puzzles as much as I did.
[video]
[video]
Every kind. I suppose I really like the ones about food.
[video]
[video]
I could tell you one like that! Once, I was having lunch with Professor Layton, and we made a puzzle out of how much food I ordered...
[video]
Oh, yeah? Did you order a lot, then?
[video]
[He was hungry, okay.]
[video]
What was the puzzle Professor Layton made out of it?
[video]
[video]
[video]
Sure! You have eight coins and a scale. One of the coins weighs just slightly less than the other seven. Using the scale, what is the fewest number of times you would have to weigh the coins in order to find the odd one out?
[video]
If there's a difference, then you'd notice it each time. So if you divide them equally… four to each side, then take off the four that are heavier, put two on each side, and then one, that makes three times.
[video]
But I can do it in fewer.
[video]
[video]
[video]